How do you solve for y in #ln y = 2x + 4#?
1 Answer
Mar 19, 2018
# y = e^(2x+4) #
Explanation:
We have:
# ln y = 2x+4 #
We can exponentiate (or if you prefer take anti-logarithms of) both side using base
# e^(ln y) = e^(2x+4) #
Leading to:
# y = e^(2x+4) #
