How do you graph #2x - 3y = 9# using x- and y- intercepts?
1 Answer
Mar 19, 2018
See a solution process below:
Explanation:
First, find the y-intercept: Set
Next, find the x-intercept: Set
We can next plot the two points on the coordinate plane:
graph{(x^2+(y+3)^2-0.075)((x-(9/2))^2+y^2-0.075)=0 [-20, 20, -10, 10]}
Now, we can draw a straight line through the two points to graph the line:
graph{(2x - 3y - 9)(x^2+(y+3)^2-0.075)((x-(9/2))^2+y^2-0.075)=0 [-20, 20, -10, 10]}