How do you solve the following linear system: x+y=1, 2x-3y=12?

1 Answer
Mar 20, 2018

x= 3 and y = -2

Explanation:

Let x+y=1 ----------equation (1),

and 2x-3y=12 -----------equation (2).

Multiply equation (1) by 2 and subtract the resultant equation from (2). This is eliminate one variable, i.e. x and we will get value of y. Then substitute the obtained value of y in any one original given equation to get value of x:

(1) times 2 - (2) =>

=> 2x +2y - (2x -3y) = 2- 12

=> 2x +2y -2x +3y = -10

=> 5y = -10

=> y = -2

Substituting y in (1)

(1) => x + (-2) = 1

=> x = 1+2 =3

therefore x= 3 and y = -2