How do you factor the expression #9x^2 - 16#?

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Answer 1 · 2018-03-20T07:12:57

#(3x+4)(3x-4)#

#9x^2-16#

#=> (3x)^2-(4)^2#

The identity for #a^2-b^2# is equal to

#(a+b)(a-b)#.

Here , #a=3x# and #b=4#.

So , we get #(3x)^2-(4)^2#

#=> (3x+4)(3x-4)#