Question

How do you simplify `14+ ( 1- 5) ^ { 2} \div 2`?

Answer 1

`22`

Explanation:

P arentheses
E xponents
M ultiplication
D ivision
A ddition
S ubtraction

`14+(1-5)^2-:2`

`=14+(-4)^2-:2`

`=14+16-:2`

`=14+8`

`=22`

Answer 2

`22`

Explanation:

Using order of operations, we will solve this equation. The easiest way to remember the order of operations is by the acronym PEDMAS:
`color(blue)"P"` `"arentheses"`
`color(blue)"E"` `"xponents"`
`color(blue)"D"` `"ivision"` and `color(blue)"M"` `"ultiplication"` (left to right)
`color(blue)"A"` `"ddition"` and `color(blue)"S"` `"ubtraction"` (left to right)

We have parentheses, so solve that first:
`14+(1−5)^2÷2`
`14+(-4)^2÷2`

Now exponents:
`14+(-4)^2÷2` (note: a negative number squared results in a positive number)
`14+16÷2`

Now division:
`14+16÷2`
`14 + 8`

And lastly addition:
`14 + 8 = 22`