How do you graph #y=-2x-3#?

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Answer 1 · 2018-03-20T23:13:47

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y = (-2 * 0) - 3#

#y = 0 - 3#

#y = -3# or #(0, -3)#

Second Point: For #x = -1#

#y = (-2 * -1) - 3#

#y = 2 - 3#

#y = -1# or #(-1, -1)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+3)^2-0.035)((x+1)^2+(y+1)^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y + 2x + 3)(x^2+(y+3)^2-0.035)((x+1)^2+(y+1)^2-0.035)=0 [-10, 10, -5, 5]}