How do you solve #3( 2x - 4) > 3x + 3#?

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Answer 1 · 2018-03-21T07:41:03

#x > 5#

Expand both sides before solving. So the inequality becomes

#6x-12> 3x +3#

Move the numerical terms to the right-hand side and the #x#'s to the other side. So we would get:

#3x>15#

Then divide both sides by #3# to get #x#. The answer would be

#x> 5#

Answer 2 · 2018-03-21T07:42:22

x>5

Treat greater than as an equals
#=6x-12>3x+3#
#2x-4>x+1#
#x>5#