How do you solve #-\frac { 1} { 4} + u \leq \frac { 3} { 8}#?

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Answer 1 · 2018-03-21T13:35:31

see a solution step below..

#-1/4 + u <= 3/8#

Multiplying through by their LCM..

The LCM of #4 and 8 rArr 8#

Therefore;

#8(-1/4) + 8(u) <= 8(3/8) -> "multiplying through by LCM"#

#cancel8^2(-1/cancel4) + 8(u) <= cancel8(3/cancel8)#

#2(-1) + 8u <= 3 -> "simplifying"#

#-2 + 8u <= 3#

#-2 + 2 + 8u <= 3 + 2 -> "adding 2 to both sides"#

#8u <= 5#

#(8u)/8 <= 5/8 -> "dividing both sides by 8"#

#(cancel8u)/cancel8 <= 5/8#

#u <= 5/8#