How do you solve # sqrt3cscx-2=0#?
1 Answer
Explanation:
First, let's isolate
#sqrt3cscx - 2 = 0#
#sqrt3cscx = 2#
#cscx = 2/sqrt3#
Now, since we know that
#1/cscx = 1/(2/sqrt3)#
#sinx = sqrt3/2#
Now, we can see that our solution set will be all points where
The two points with a y-coordinate of
Therefore, our solution is:
#{x | x = pi/3, x = (2pi)/3}#
One last touch: remember that the values of all trig functions are the same if you add
#{x | x = pi/3 + 2kpi, " " x = (2pi)/3 + 2kpi}, " for any integer " k#
Or if you REALLY want to translate the last part into fancy math symbols:
#{x | x = pi/3 + 2kpi, " " x = (2pi)/3 + 2kpi}," " forall k in ZZ#
Final Answer