Answer Part (b)?

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1 Answer
Mar 22, 2018

See below.

Explanation:

If

a_n = 2n^2-3n+5 then

a_(n+1) = 2(n+1)^2-3(n+1)+5 = 2n^2+4n+2-3n-3+5 = a_n + 4n-1 = 4(n+1)-5

but we know that

a_n = a_(n-1)+4n-5

and we have shown that for n ge 2

a_(n-1)= a_n + 4(n+1)-5

The final arrangements for the finite induction demonstration are left to the reader.