Question

How do you simplify `16x ^ { 2} \div 16x ^ { 5}`?

Answer 1

`(16x^2)/(16x^5)=1/x^3`

Explanation:

`(16x^2)/(16x^5)=16xx x^2 xx 1/16 xx x^(-5)`

You can now use exponent rules to multiply `16` by `1/16` and `x^2` by `x^(-5)` and get `1` and `x^(-3)`.

So, `1xxx^(-3)=1/(x^3)`.