What is the equation of the line perpendicular to y - 4 = 0y4=0 and passing through (-1, 6)? Please show working.

1 Answer
Mar 22, 2018

x=-1x=1

Explanation:

"note that "y-4=0" can be expressed as "y=4note that y4=0 can be expressed as y=4

"This is a horizontal line parallel to the x-axis passing "This is a horizontal line parallel to the x-axis passing
"through all points in the plane with a y-coordinate "=4through all points in the plane with a y-coordinate =4

"A line perpendicular to "y=4" must therefore be a "A line perpendicular to y=4 must therefore be a
"vertical line parallel to the y-axis"vertical line parallel to the y-axis

"such a line has equation "x=c" where c is the value"such a line has equation x=c where c is the value

"of the x-coordinate the line passes through"of the x-coordinate the line passes through

"here the line passes through "(-1,6)here the line passes through (1,6)

"the equation of the perpendicular line is therefore"the equation of the perpendicular line is therefore

color(red)(bar(ul(|color(white)(2/2)color(black)(x=-1)color(white)(2/2)|)))
graph{(y-0.001x-4)(y-1000x-1000)=0 [-10, 10, -5, 5]}