How do you divide #\frac { 2 g + 1 0 } { 4 g}-: \frac { 2 } { 8 g }#?

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Answer 1 · 2018-03-22T18:31:48

#=2(g+5)#

Or #2g+10#

#(2g+10)/(4g) div 2/(8g)#

Factorise the numerator and then multiply by the reciprocal

#=(2(g+5))/(4g) xx (8g)/2#

Now you can cancel the common factors

#=(cancel2(g+5))/cancel(4g) xx cancel(8g)^2/cancel2#

#=2(g+5)#

Or you can write it as #2g+10#