Can some one help me with this question ??

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1 Answer
Shulgin
Mar 22, 2018

See below

Explanation:

So in the first reaction where we have #Br_2# and light two things will happen. First of all the C where there are two #CH_3# bonded to will split up, losing its hydrogen #H# leaving it with a +1 charge. Than #Br# will make an attack, forming a bond with the +1 charged carbon. Resulting in the following molecule:
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In the second reaction we will just remove the #Br# and replace it with an an #OH# in the same place.
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Hope it helps and write if you need help naming them

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