Question

How do you find in standard form a line that is parallel to `-2x-3y = -2` and passing through (2, -2)?

Answer 1

`-2x-3y=2`

Explanation:

First, we need to find the slope of the line that it is parallel to, as this line will have the same slope.
`-2x-3y=-2`
`3y=-2x-2`
`y=-2/3x-2/3`
Therefore, `m=-2/3`
We can use point-slope form at first before we convert it to standard form.
`y-y_1=m(x-x_1)`
`y+2=-2/3(x-2)`
`y+2=-2/3x+4/3`
`3y+6=-2x+4` multiply by 3 to get rid of fractions
`-2x-3y=2`