How do you solve #sqrt(x+1) =sqrt(x-5)#?

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Answer 1 · 2018-03-23T16:33:24

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#sqrt(x+1) = sqrt(x-5)#

In order to eliminate a square root we can square the root.
Whatever you do on the left, you also do on the right.

#sqrt(x+1)^2 = (sqrt(x-5))^2#

This leaves us with the equation

#x+1 = x-5#

Combine like terms by using the additive/subtractive inverse.

#cancelxcancel(+1) cancel(-x) cancel(-1)= cancelx -5 cancel(-x) -1 #

This leaves

#0 != -6#
No Solution