How do you solve #[(X+2) / (X-1)] = [1/2]#?

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Answer 1 · 2018-03-23T23:44:09

#X=-5#

Given:

#(X+2)/(X-1) = 1/2#

Multiply both sides by #2(X-1)# to get:

#2(X+2) = X-1#

Multiplying out the left hand side, this is:

#2X+4 = X-1#

Subtract #X+4# from both sides to get:

#X = -5#