Question

How do you graph `y=5sin(x-7pi/6) + 3`?

Answer 1

As below.

Explanation:

Standard form of equation is `y = A sin (Bx - C) + D`

Given equation is `y = 5 sin (x - ((7pi)/6)) + 3`

`Amplitude = |A| = 5`

`"Period " = P = (2pi) / |B| = 2pi`

`"Phase Shift " = P_s = (-C)/ B = ((7pi)/6) / 1 = (7pi)/6, " to the right"`#

`"Vertical Shift " = V_s = D = 3`

graph{5 sin (x - ((7pi)/6)) + 3 [-10, 10, -5, 5]}