How do you simplify #5/(x+3) - 2/(x-1)#?

2 Answers
Mar 24, 2018

#(3x-11)/((x+3)(x-1))#
Where #x!=-3 or 1#

Explanation:

#(3x-11)/((x+3)(x-1))#
Where #x!=-3 or 1#
The reason x can't be -3 or 1 is because if this happens the denominator will become #0# and anything with denominator #0# becomes undefined.
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Mar 24, 2018

The given question states :
#5/(x+3)-2/(x-1)#

So, processing further:
#rArr(5 xx( x-1)-2 xx( x+3))/((x+3) xx (x-1)#

#rArr((5x-5 )-(2x+6))/((x+3) ( x-1)#

#rArr(5x-5-2x-6)/((x+3)(x-1)#

#rArr(5x-2x -5-6)/((x+3)(x-1)#

#rArr(3x-11) /((x+3) (x-1))#

#rArr(3x-11) /(x^2-x+3x-3)#

#rArr(3x-11) /(x^2+2x-3)#

I am honored to help you.
If my answer really helps you, please let me know:)