How do you solve the following system?: # -9x - 3y = 2 , -7/2x - 1/2y = -3 #

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Answer 1 · 2018-03-24T14:46:44

#x= -2//3, y=4//3#

Simplifying first equation,

#-9x-3y=2#

Dividing by 3 on both sides,

#rArr -3x-y=2//3 .............(1)#

Now for second equation,

#-7x//2-y//2=-3#

Multiplying both sides by 2,

#rArr -7x-y=-6 .............(2)#

Now adding (1) and (2), we get:

#(-3x-y) + (-7x-y)=2//3 + (-6)#

#rArr -10x = -20//3#

#rArr x=-2//3#

Now, put #x=-2//3# in (1),

#-3*(-2//3)-y=2//3#

#rArr y=4//3#

#:. x= -2//3, y=4//3#