Question

If a spring has a constant of `4 (kg)/s^2`, how much work will it take to extend the spring by `73 cm`?

Answer 1

1.0658 J

Explanation:

Spring constant, `k = 4 (kg)/s^2`
Spring initial position, `x_i = 0 m`
Spring final position, `x_f = 0.73 m`

Work done by a spring can be found using the equation:
`W_(sp) = 1/2k(X_f^2 - X_i^2)`

Plug in your values:
`W_(sp) = 1/2(4)((0.73)^2 - (0)^2)`
`W_(sp) =1.0658` J (Don't forget about units)

Hope this helps!