Question

How do you solve `3log2x=4`?

Answer 1

`x=(1/2)*10^(4/3)`

Explanation:

Assuming the logarithm as Common Logarithm (With base `10`),

`color(white)(xxx)3log2x=4`

`rArr log2x=4/3` [Transposing The 3 to R.H.S.]

`rArr 2x=10^(4/3)` [According to The Definition of Logarithm]

`rArr x=(1/2)*10^(4/3)` [Transposing 2 to R.H.S]

Hope this helps.