Question

How do you factor `256z^2-4-192z^2+3`?

Answer 1

Simplify & use identities

Explanation:

=`256z^2-192z^2-1`

= `64z^2-1`

Use `a^2-b^2=(a+b)(a-b)`

= `(8z)^2-(1)^2`

`(8z+1)(8z-1=0`

`z=1/8 , -1/8`