Count the number of terms in the expression.
#color(blue)([(8+5) (6-2) ^2])color(red)( - (4times17 div2))" "larr# there are 2 terms
Simplify each term to a single answer which will be added or subtracted in the last step.
In each term the order to follow is:
Brackets first - work from the innermost bracket
Multiply and divide
#" "color(blue)([(8+5) (6-2) ^2])color(red)( - (4times17 div2))#
#color(white)(wxxw)darrcolor(white)(wxw)darrcolor(white)(wxxxw)darr#
#=color(blue)([(13) xx" " (4) ^2])" "color(red)( - (68 div2))#
#color(white)(wxxw)darrcolor(white)(wxw)darrcolor(white)(wxxxw)darr#
#=color(blue)([(13)""xx" " (16)])" "color(red)( - (34))#
#color(white)(wxxxxw)darr#
#=color(white)(xxxx)color(blue)(208)color(white)(xxxx)color(red)( - 34)#
#=174#
