What are the intercepts for 2x-y=12x−y=1?
2 Answers
(0.5, 0) and (0, -1)
graph{2x-y=1 [-10, 10, -5, 5]}
Explanation:
I would always recommend sketching the graph yourelf if you can.
If you can't plot the graph yourself, substitute
(because graph intercepts
At
At
Hope this helps!
Explanation:
"to find the intercepts, that is where the graph crosses"to find the intercepts, that is where the graph crosses
"the x and y axes"the x and y axes
• " let x = 0, in the equation for y-intercept"∙ let x = 0, in the equation for y-intercept
• " let y = 0, in the equation for x-intercept"∙ let y = 0, in the equation for x-intercept
x=0rArr0-y=1rArry=-1larrcolor(red)"y-intercept"x=0⇒0−y=1⇒y=−1←y-intercept
y=0rArr2x-0=1rArrx=1/2larrcolor(red)"x-intercept"y=0⇒2x−0=1⇒x=12←x-intercept
graph{(y-2x+1)((x-1/2)^2+(y-0)^2-0.04)((x-0)^2+(y+1)^2-0.04)=0 [-10, 10, -5, 5]}