How do you multiply #sqrt(-16) / sqrt(2) #?

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Answer 1 · 2018-03-25T19:37:59

#=>2sqrt(2)i#

We start with:

#=>sqrt(-16)/sqrt(2)#

We can combine the square root:

#=>sqrt(-16/2)#

Dividing the argument of the root:

#=>sqrt(-8)#

We can find factors to potentially pull out of the square root.

#=>sqrt(2xx4xxi^2)#

Simplifying:

#=>2sqrt(2)i#