How do you solve 24+x^2=10x?

3 Answers
Mar 25, 2018

You have to pass 10x to the left hand and equal the quadratic equation to 0
24 + x^2-10x=0
then you rearrenge it
x^2-10x+24=0

Then you have to think about two numbers that when you times them you get as the answer 24
and when you add them -10

The numbers are -6 and -4
(-6)x(-4)=24
(-6) +(-4)=-10
The final working is :
x^2-10x+24=(x-6)(x-4)

So the answers are:
x-6=0
x=6

x-4=0
x=4

Mar 25, 2018

x=6 or x=4

Explanation:

24+x^2=10x

Put into standard form, color(violet)(ax^2+bx+c=0)

x^2-10x+24=0

darrFactor using criss-cross method of factoring

1color(white)(XX)-6

1color(white)(XX)-4

-4-6

=-10 lArr same number as our b-value in our rearranged equation.

:. 24+x^2=10x is color(orange)"(x-6)(x-4)"

Further on, finding the x-intercepts of (x-6)(x-4)=0

x-6=0 color(white)(XXXXXX) and color(white)(XXXXXX)x-4=0

x=6color(white)(XXXXXXXXXXXXXXXXX)x=4

:. the zeros are color(blue)6 and color(blue)4.

Mar 25, 2018

x=6 or x=4

Explanation:

Here,

24+x^2=10x

=>x^2-10x+24=0

Now,

(-6)(-4)=24 and (-6)+(-4)=-10

So,

x^2-6x-4x+24=0

=>x(x-6)-4(x-6)=0

=>(x-6)(x-4)=0

=>x-6=0 or x-4=0

=>x=6 or x=4