Question

How do you simplify `\frac { 8b c ^ { 4} d ^ { 2} } { 8b ^ { 2} c ^ { 3} d ^ { 9} }`?

Answer 1

`=>(c)/(bd^7)`

Explanation:

`=>\frac { 8b c ^ { 4} d ^ { 2} } { 8b ^ { 2} c ^ { 3} d ^ { 9} }`

First, we can divide out the `8`s.

`=>(bc^4d^2)/(b^2c^3d^9)`

Next, let's simplify the `b` terms. The difference of powers between numerator and denominator is `1-2 = -1`. So we can write `b^1 = b` in the denominator.

`=>(c^4d^2)/(bc^3d^9)`

For `c` terms, the difference in powers is `4-3 = 1`. So we can write `c^1=c` in the numerator.

`=>(cd^2)/(bd^9)`

Last, the `d` terms. The difference in powers is `2-9 = -7`. So we can write `d^7` in the denominator.

`=>(c)/(bd^7)`