Can you find the value of k?

Question

When #2x^4-kx^3+3x^2-x# is divisible by #x-3#

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Answer 1 · 2018-03-26T08:10:40

#color(magenta)(k=186/27 or k=6.8888...#

Since #x-3# is a factor of #2x^4−kx^3+3x^2−x# when you plug in #x=3#

#2(3)^4−k(3)^3+3(3)^2−(3)=0#

#2(81)-k(27)+3(9)-3=0#

#162+27-3=27k#

#27k=186#

#k=186/27#

#color(magenta)(k=186/27 or k=6.8888...#

~Hope this helps! :)