Question

What is the distance, in units, between (–2, 8) and (–10, 2) in the coordinate plane?

Answer 1

The distance is 10 units.

Explanation:

distance between `A(x_1, y_1) and (x_2, y_2)` on xy plane:

`d = sqrt((x_1-x_2)^2 + (y_1-y_2)^2) = sqrt((x_2-x_1)^2 + (y_2-y_1)^2)`

`d = sqrt((-2 - (-10))^2 + (8 - 2)^2)`

`d = sqrt 100 = 10`