Question

How do you find the domain and range of `f(x) =sqrt(36-x^2)`?

Answer 1

The domain is `-6 <= x <=6`
in interval form: `[-6,6]`

Explanation:

The square roots are only defined when the expression under the square root is non-negative.
This function is defined when: `36 - x^2 >=0`
`x^2 <= 36`
`abs x <= 6`
`-6 <= x <=6`