How do you simplify #cos x + sin x tan x#?
1 Answer
Mar 26, 2018
Explanation:
#"using the "color(blue)"trigonometric identities"#
#•color(white)(x)tanx=sinx/cosx" and "secx=1/cosx#
#•color(white)(x)sin^2x+cos^2x=1#
#rArrcosx+sinx xx sinx/cosx#
#=cos^2x/cosx+sin^2x/cosx#
#=(cos^2x+sin^2x)/cosx=1/cosx=secx#
