Determine domain? #f(x)=2+sqrt(x-1)#

determine domain?
#f(x)=2+sqrt(x-1)#

1 Answer
Zachary
Mar 26, 2018

Domain: #x>=1#

Explanation:

The only rule to consider when finding the domain is that for these purposes, you cannot have a negative number under the #sqrt#. Knowing this, you can deduce that for #f(x)=sqrt(x-1)#(the #2# doesn't matter for the domain), #f(x)# must be at least #0#. #sqrt0# is #0#, so #x# can be any value greater than or equal to #1#, because anything less than 1 would give a non-real value for #sqrt(x-1)#. So the domain is #x>=1#.

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