How do you simplify #9+ (x-3)/ (x+2)#?

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Answer 1 · 2018-03-27T00:16:10

The simplified expression is #(10x+15)/(x+2)#.

Multiply #9# by #(x+2)/(x+2)# to get a common denominator, then combine the two fractions:

#color(white)=9+(x-3)/(x+2)#

#=9color(red)(*((x+2))/(x+2))+(x-3)/(x+2)#

#=(9(x+2))/(x+2)+(x-3)/(x+2)#

#=(9x+9*2)/(x+2)+(x-3)/(x+2)#

#=(9x+18)/(x+2)+(x-3)/(x+2)#

#=((9x+18)+(x-3))/(x+2)#

#=(9x+18+x-3)/(x+2)#

#=(9x+x+18-3)/(x+2)#

#=(10x+18-3)/(x+2)#

#=(10x+15)/(x+2)#

That's it. Hope this helped!