Let #S_n# be a polygonal sequence built by the Series of the Arithmetic Sequence #S_n = Sigma_i^(n)a_i # where #a_n = {1, 4, 7, 10, 13, ...}#, find the generating formula for polygonal sequence #S_n#?

Let #S_n# be a polygonal sequence built by the Series of the Arithmetic Sequence given by: #a_n = {1, 4, 7, 10, 13, ...}#. #S_n = Sigma_i^(n)a_i # find the generating formula for polygonal sequence #S_n#?

1 Answer
Mar 27, 2018

#S_n = (3n^2-n)/2#

Explanation:

Given : an arithmetic sequence with common difference #d = 3#:

#a_n = {1,4,7,13,...}# and it's
Series #S_n = sum_(i=1)^(i=n) a_n = 1+4+7+13+ cdots+n #
Required : #S_n# for all #n in ZZ#

Solution:
Strategies: Obtain the #S_n# from the Sum (series) of the arithmetic sequence

Strategy :
#S_n = (a_1 +a_n)/2 n " "#(1)
This the area of Trapezoid under the blue sequence...
Now the equation of a arithmetic sequence is:
#a_n = a_1 + d(n-1) " "# (2)
with #d=3#
#a_n = 3n-2 " "# (3)
inserting (3) into (1)
#S_n = (1+3n-2)/2n = (3n-1)/2 n = (3n^2-n)/2#

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