How do you use the distributive property to simplify #4(2a -3b) #?
2 Answers
Mar 27, 2018
Explanation:
Mar 27, 2018
Explanation:
#"multiply each term in the parenthesis by the 4"#
#rArrcolor(red)(4)(2a-3b)#
#=(color(red)(4)xx2a)+(color(red)(4)xx-3b)#
#=8a+(-12b)=8a-12b#