What is the y-intercept of #y=-2(8-x)-9#?

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Answer 1 · 2018-03-27T15:47:29

#color(blue)(-25)#

The #y# intercept occurs where #x=0#

#:.#

#y=-2(8-(0))-9#

#y=-16-9#

#color(blue)(y=-25)#

Answer 2 · 2018-03-27T15:50:05

#-25#

Expand the bracket

#-2(8-x)#

so

#y = -2 (8 - x) - 9 #

becomes

#y = - 16 + 2x - 9#

Now,

#- 16 - 9 = - 25#

so

#y = - 16 + 2x - 9#

becomes

#y = 2x - 25#

The slope-intercept equation of a straight line is

#y = mx + c#

where #m# is the gradient of the line and #c# is the #y#-intercept. So your answer is #- 25#.