How would I write 3/8^2.5 in radical form?

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Answer 1 · 2018-03-28T03:33:52

= #(sqrt(6))^(5)/1024#

Or,

= #(sqrt(6^5)/1024)#

#(3/8)^2.5# #"=># #(3/8)^(5/2)#

= #sqrt((3/8)^5)#

= #(sqrt(3/8))^(5)#

= #(sqrt((3x8)/(8x8)))^(5)#

= #(1/8(sqrt(6x4)))^(5)#

= #(2/8(sqrt(6)))^(5)#

= #(1/4(sqrt(6)))^(5)#

= #(sqrt(6))^(5)/1024#

Or,

= #(sqrt(6^5)/1024)#