How do you factor completely 6x^2+7x+2?

2 Answers
Mar 28, 2018

(2x+1)(3x+2)

Explanation:

"for a quadratic in "color(blue)"standard form"

•color(white)(x)ax^2+bx+c color(white)(x);a!=0

6x^2+7x+2larr"is in standard form"

"with "a=6, b=7" and "c=2

color(blue)"to factorise"

"consider the factors of the product ac which sum to b"

rArrac=6xx2=12" and + 4, + 3 sum to + 7"

6x^2+3x+4x+2larrcolor(blue)"split middle term"

=color(red)(3x)(2x+1)color(red)(+2)(2x+1)larrcolor(blue)"factor in groups"

"take out a common factor "(2x+1)

=(2x+1)(color(red)(3x+2))

rArr6x^2+7x+2=(2x+1)(3x+2)

Mar 28, 2018

(2x+1)(3x+2)

Explanation:

By sum & product

= 6x^2+4x+3x+2

= 2x(3x+2)+1(3x+2)

= (2x+1)(3x+2)

Hope this helps!