How do you combine #11/(5x)-1/(5x)#?

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Answer 1 · 2018-03-28T09:42:27

#2/x#

#11/(5x)-1/(5x)#

Since the denominator is constant, you can just combine as such,

#(11-1)/(5x)#

Simplify,

#10/(5x)#

Divide,

#2/x#

Answer 2 · 2018-03-28T10:56:13

#2/x#

#11/(5x) - 1/(5x)#

first you find the LCM, in this case the LCM is #5x#

then you divide the LCM with the denominator and multiply it with the numerator;

#(11 - 1)/(5x)#

#10/(5x)#

#(2 xx 5)/(5 xx x)#

#(2 xx cancel5)/(cancel5 xx x)#

#2/x#