How do you use synthetic division to divide #(2x^3-x^2+5x-12) /(2x - 3) #? Precalculus Real Zeros of Polynomials Synthetic Division 1 Answer Cem Sentin Mar 28, 2018 Quotient is #x^2+x+4# and remainder is #0#. Explanation: #2x^3-x^2+5x-12# =#2x^3-3x^2+2x^2-3x+8x-12# =#x^2*(2x-3)+x*(2x-3)+4*(2x-3)# =#(2x-3)*(x^2+x+4)# Hence quotient is #x^2+x+4# and remainder is #0#. Answer link Related questions What is synthetic division? What are common mistakes students make with synthetic division? How do I find the quotient and remainder using synthetic division? How do you write the remainder in synthetic division? How do I find the quotient #(x^3+5x^2+x-15)/(x+3)# by using synthetic division? How do I find the roots of a polynomial function by using synthetic division? How can synthetic division be used to factor a polynomial? How do I use synthetic division to find #p(-3)# for #p(x)=x^4-2x^3-4x+4#? Use synthetic division to find #p(4)# for #p(x)=x^4-2x^3-4x+4#? How do you use synthetic division to evaluate #f(3)# given that #f(x)=x^3+2x^2-7x+8#? See all questions in Synthetic Division Impact of this question 1796 views around the world You can reuse this answer Creative Commons License