Question

If sec(t) = 3, how do you find the exact value of `csc(90 - t )`?

Answer 1

`sec(t) = 3`
`=> cos(t) = 1/3`

now, we know, `sin(90-x) = cosx`

`sin(90-t) = cos(t) = 1/3`

`csc(90-t) = 1/sin(90-t) = 3`