How do you simplify #3i^2 - 4i^4 + 5i^8 + 3#? Precalculus Complex Numbers in Trigonometric Form Powers of Complex Numbers 1 Answer José F. Mar 28, 2018 7 Explanation: since that #i^(2n)# is equal to 1, so #3i^2-4i^4+5i^8+3# is equal to #3-4+5+3# #7# Answer link Related questions How do I use DeMoivre's theorem to find #(1+i)^5#? How do I use DeMoivre's theorem to find #(1-i)^10#? How do I use DeMoivre's theorem to find #(2+2i)^6#? What is #i^2#? What is #i^3#? What is #i^4#? How do I find the value of a given power of #i#? How do I find the #n#th power of a complex number? How do I find the negative power of a complex number? Write the complex number #i^17# in standard form? See all questions in Powers of Complex Numbers Impact of this question 1534 views around the world You can reuse this answer Creative Commons License