Question

How do you find the slope of a tangent line to the graph of the function `f(x)=3-5x` at (-1,8)?

Answer 1

slope `= -5`

Explanation:

Given: `f(x) = 3-5x` at `(-1, 8)`

Usually we find the slope by finding the first derivative and evaluating it at the `x` value of the point: `f'(-1)`

In the given case, we have a linear equation: `y = mx + b` The slope of the line is given as `m = -5`. This slope is the same everywhere along the line.

If you find `f'(x) = -5`.

`f'(-1) = -5` since it is a constant slope.