Question

Verify the change in oxidation number.......2Cu2O(s)+Cu2S(s)---6Cu (s)+SO2(s)?

Answer 1

Here's what I get.

Explanation:

The oxidation numbers

The oxidation numbers of the atoms in the equation are

`stackrelcolor(blue)("+1")("Cu")_2stackrelcolor(blue)("-2")("O") + stackrelcolor(blue)("+1")("Cu")_2stackrelcolor(blue)("-2")("S") → stackrelcolor(blue)(0)("Cu") + stackrelcolor(blue)("+4")("S")stackrelcolor(blue)("-2")("O")_2`

Changes in oxidation number

`"Cu"` in `"Cu"_2"O"`: Changes from +1 to 0, Change = -1.
`"Cu"` in `"Cu"_2"S"color(white)(l)`: Changes from +1 to 0, Change = -1.
`"S"` in `"Cu"_2"S"color(white)(m)`: Changes from -2 to +4, Change = +6