How do you simplify #((3x^2)(6y^4)(z^2))/((12x)(3y^2)(z))#?

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Answer 1 · 2018-03-29T10:16:37

#(2xy^2z)/(4x)#

To simply we know that the numbers divide #3/12=1/4#

We also know that for the exponents they subtract when we divide #y^4/y^2=y^(4-2)=y^2#

So #(3x^2)/(12x)=(1x)/4#,

#(6y^4)/(3y^2)=2y^2#

#z^2/z=z#

So if we mutiply all these part together we get

#(2xy^2z)/(4x)#