How do you find x when y= -2, -1, 0 and 1 given #4(5-y)=14x+3#?

1 Answer
Mar 29, 2018

See below for a detailed solution:

Explanation:

#color(green)(4(5-y)=14x+3#

#=20-4y=14x+3#

#14x=20-4y-3#

#14x=17-4y#

#color(red)(x=(17-4y)/14#

Part 1 - When #color(blue)(y=-2#

#x=(17-4y)/14#

#x=(17-4xx-2)/14#

#x=(17+8)/14#

#color(magenta)(x=25/14=1 11/14#

Part 2- When #color(blue)(y=-1#

#x=(17-4y)/14#

#x=(17-4xx-1)/14#

#x=(17+4)/14#

#color(magenta)(x=21/14 =3/2=1 1/2#

Part 3 - When #color(blue)(y=0#

#x=(17-4y)/14#

#x=(17-4xx0)/14#

#x=(17+0)/14#

#color(magenta)(x=17/14=1 3/14#

Part 4 - When #color(blue)(y=1#

#x=(17-4y)/14#

#x=(17-4xx1)/14#

#x=(17-4)/14#

#color(magenta)(x=13/14#

~Hope this helps! :)