How do you find the slope given #2x-3y=12#?

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Answer 1 · 2018-03-29T11:19:56

#2/3#

So you want to put the equation back into the linear equation #y=mx+c#

As #m# is the slope

Minus #2x# from both sides
#-3y=12-2x#

Divide by -3 on both sides

#y=(12-2x)/-3#

Break the Right hand side into two fractions

#y=12/-3+(-2)/-3x# or #y=(-2)/-3x+12/-3#

Simplfy

#y=2/3x-4#

So the slope is #2/3#