How do you graph the inequality #x + 2y< = -4#?

1 Answer
Mar 29, 2018

See below.

Explanation:

The solution of this type of inequations is a plane region.

Allways proceed as follows.

1.- leave #y# alone in one side of symbol #<#

#2y<=-4-x#; that means #y<=-4/2-x/2=-2-x/2#

2.- Treat this last expresion as a normal function., It's say

#y=-x/2-2# and plot it in the coordinate's plane

3.- finally, consider the symbol #<=#. If #y<=expresion#, then the region-solution falls of below the line. If the symbol is #>=# the solution is above the line. If symbols include #=# the line is part of solution, if not, then the line is not included in solution (mark it with a dotted line).

See the graph (The dark blue area is the solution)
graph{y<=-x/2-2 [-10, 10, -5, 5]}