How do you factor #49x^2-36#?

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Answer 1 · 2018-03-29T13:22:07

#(7x+6)(7x-6)#

#49x^2−36 =#
#7^2x^2−6^2 =#
#(7x)^2-6^2=#
#(7x+6)(7x-6)#
because #a^2-b^2=(a+b)(a-b)#

Answer 2 · 2018-03-29T13:24:10

#(7x+6)(7x-6)#

Note that #49=7^2# and #36=6^2#

So we have #7^2x^2 - 6^2 = (7x)^2-6^2#.

This is in the form #a^2-b^2# which can be factored to #(a+b)(a-b)#

So here we have #a = 7x# and #b = 6#, so that would be #(7x+6)(7x-6)#